In beaker A, a solution is made by dissolving 2-3
crystals of potassium permanganate in 100 mL of
water. 10 mL of this solution is added in another
beaker 'B' and the volume is made 100 mL by adding
water. Same process is repeated again by taking
10 mL of solution from beaker B to C and
subsequently from beaker C to D. The solution with
the least concentration is
Answers
D is the only solution with least concentration because the particles cannot divide into smaller pieces further.
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This is a typical case of series dilution.
As per question one must notice the initial amount of potassium parmanganate is constant.
When 10ml from beaker A is taken into beaker B; as the solution in beaker A was homogenous, part of potassium parmanganate came into beaker B is actually 1/10th of the total parmanganate amount.
Same procedure is followed upto beaker D. Thus mathematically beaker D contains 1/1000 amount of parmanganate present in beaker A = 1/100 amount of parmanganate present in beaker C = 1/10 amount of parmanganate present in beaker B. Thus containing the least parmanganate concentration.