Question

if the radius of the sphere is increased by 100% the volume of the correspondimg sphere is increased by ​

Answer 1

Solution

Volume of the sphere

$v1= \frac{4}{3} \pi \: r {}^{3}$

now after increasing the radius by 100% volume becomes.

$v2 = \frac{4}{3} \times \pi \times (r + r) {}^{3} = 8 \times ( \frac{4}{3} \times \pi \: \times r {}^{3} ) \\ = > v2 = 8 \times v1$

the volume of the correspondimg sphere is increased by 800%

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Hope this helps you ✌️