if the rank correlation coefficient between marks in management and maths for a group of students is 0.6 and the sum of squares of the differences in ranks is 66 , what is the number of stidents of group
Answers
the number of students of group = 10 if the rank correlation coefficient = 0.6 & sum of squares of the differences in ranks is 66
Step-by-step explanation:
rank correlation coefficient = 1 - 6 ∑ (di)² / (n(n² - 1))
n = number of stidents of group
∑ (di)² = sum of squares of the differences in ranks = 66
rank correlation coefficient = 0.6
=> 0.6 = 1 - 6 ∑ (di)² / (n(n² - 1))
=> -0.4 = -6 * 66 / (n(n² - 1))
=> (n(n² - 1)) = 990
=> (n(n² - 1)) = 10 * 99
=> (n(n² - 1)) = 10 * (100 - 1)
=> (n(n² - 1)) = 10 * (10² - 1)
=> n = 10
the number of students of group = 10
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Answer:
The number of students of group = 10 if the rank correlation coefficient = 0.6 & sum of squares of the differences in ranks is 66
Step-by-step explanation:
Rank correlation coefficient = 1 - 6 ∑ (di)² / (n(n² - 1))
n = number of stidents of group
∑ (di)² = sum of squares of the differences in ranks = 66
rank correlation coefficient = 0.6
=> 0.6 = 1 - 6 ∑ (di)² / (n(n² - 1))
=> -0.4 = -6 * 66 / (n(n² - 1))
=> (n(n² - 1)) = 990
=> (n(n² - 1)) = 10 * 99
=> (n(n² - 1)) = 10 * (100 - 1)
=> (n(n² - 1)) = 10 * (10² - 1)
=> n = 10
Therefore, the number of students of group = 10.
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