The velocity of flow of water in a pipe of 150 mm dia is 0.3m/sec, a diaphragm with a central hole 80mm in diameter is placed in the pipe obstructing the flow. With coefficient od contraction Cc=0.60, the loss of head from Vena Contracta to a point downstream will be ?
Answers
Solution:
Diameter of pipe = 150 mm = 150 / 1000 = 0.15 m
Diameter of Diaphragm with a central hole = 80 mm = 80 / 1000 = 0.08 m
Area of pipe = = = 0.0176 m²
Area of central hole present in diaphragm = = = 0.005 m²
where ,
v = Velocity = 0.3 m/s
g = Acceleration due to gravity = 9.8 m/s²
A = Area of pipe
a = Area of central hole present in diaphragm
= Coefficient of contraction = 0.60
The loss of head from Vena Contracta to a point downstream will be 0.0248 m or 24.8 mm
The value of loss of head is h = 24.8 mm
Explanation:
- The formula for velocity is given;
- h[obstruction] = V^2 / 2g [A / Cc (A-a)]^2
- Here
- V = velocity
- A = area of pipe
- a = area of central pipe
- cc = Coefficient of contraction
Now put the values in the formula.
h[obs] = 0.3^2 / 2 x 9.8 [ 0.0176 / 0.06 x (0.0176 - 0.005)]^2
h[obs] = 0.09 / 19.6 [176 x 10 / 6 x 126]^2
h [obs] = 9 x 10 x 1760 x 1760 / 196 x 100 x 756 x 756
h[obs] = 0.0248 m
convert into millimeters b multiplying with 1000
h[obs] = 24.8 mm