If the rate of diffusion of a gas X is 3 times greater than the rate of diffusion of O2 gas,find the molar mass of X gas
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Answer:
16/9 g
Explanation:
by Graham's law of diffusion
ratio of Rate of diffusion is inversely proportional to square root of molar mass
Let the molar mass of the unknown gas be M g.
let diffusion of O2 be x and the other be 3x
therefore,
x/3x = √M/√16
=> 1/3 = √M/√16
=> 1/9 = M/16 ( squaring both sides)
=> M = 16/9
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