Question

If the ratios of areas of two squares is 9 : 1, then ratio of their perimeters is:
(a)
9:1
(b) 3:1
(c)
3:4
(d) 1:3​

Answer 1

Answer:

(b) 3:1

Step-by-step explanation:

Answer 2

Answer:

b) 3:1

Step-by-step explanation:

let side of 1st square be R and side of 2nd square be r

area of 1st square is R^2

area of 2nd square is r^2

therefore,

R^2/r^2=9/1

R^2=9r2

R=3r

R/r=3/1................(1)

perimeter of 1st square is 4R

perimeter of 2nd square is 4r

therefore 4R/4r=R/r=3/1..............from (1)

solution :

ratio of perimeter of square is 3:1