Question

. If the relation between the displacement x of a particle in time t is
represented by the equation x = a0 + a1t + a2t^2 the value of acceleration
of the particle is

Answer 1

Answer:

$2a^{2}$

Explanation:

We know that v = dx/dt

a = dv/dt

x = ao + a1t + a2t2

v= dx/dt = 0 + a1 + 2a2t

a=dv/dt = d/dt (a1+2a2t)

=0+2a2

Differentiation of constant is 0

So, acceleration of particle = 2a^2