If the remainder on division of x^2+2x^2+4x+3 by x-3 is 21,find the zeroes of cubic polynomials
Answers
Answered by
0
α+β+γ=−b÷a
so, sum of zeroes = -2/1 = (-2)
αβ+βγ+γα=c÷a
so, 4/1 = 4
αβγ=−d÷a
so, product of zeroes = -3/1 = (-3)
Hope it help you
I hope I make you understand your doubt
so, sum of zeroes = -2/1 = (-2)
αβ+βγ+γα=c÷a
so, 4/1 = 4
αβγ=−d÷a
so, product of zeroes = -3/1 = (-3)
Hope it help you
I hope I make you understand your doubt
Similar questions
Science,
6 months ago
Social Sciences,
6 months ago
Economy,
6 months ago
Physics,
11 months ago
Computer Science,
11 months ago
Chemistry,
1 year ago