Question

If the remainder on division of x^2+2x^2+4x+3 by x-3 is 21,find the zeroes of cubic polynomials

Answer 1

α+β+γ=−b÷a

so, sum of zeroes = -2/1 = (-2)

αβ+βγ+γα=c÷a

so, 4/1 = 4

αβγ=−d÷a

so, product of zeroes = -3/1 = (-3)

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