If the resistance of a circuit is doubled,by what factor does the power get affected?
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P = V^2/R
When resistance is doubled
P = V^2/2R
So the power is halved
When resistance is doubled
P = V^2/2R
So the power is halved
Ayushpratapsingh2210:
When the resistance will be increased then current will decrease automatically because V = IR , V is constant in both cases
Thanks!
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