if the resistance of the wire is increased by twice its length, and its cross sectioned area decreased find the new resistance.
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Answered by
0
Heyy
It's sneha
Here is ur answer
⏩ As the resistance is directly proportional to length
➡ If we increase the length twice, the resistance of conductor also become twice of its original resistance
⏩ Area of Cross section is inversely proportional to the resistance
➡ If we decrease the area, the resistance increases
Hope it helps
#sneha
It's sneha
Here is ur answer
⏩ As the resistance is directly proportional to length
➡ If we increase the length twice, the resistance of conductor also become twice of its original resistance
⏩ Area of Cross section is inversely proportional to the resistance
➡ If we decrease the area, the resistance increases
Hope it helps
#sneha
Suraj03:
what is the resistance?
Answered by
1
Let length of old wire be L1 and that of the new wire be L2.
According to the given condition,
L2 = 2× L1 ....(I)
Let the cross sectional area of old wire be A1 and that of new wire be A2
According to the given condition,
2×A2 = A1 ....(II)
We know that,
R = L/A
R2 = L2 /A2
i.e. R2 = 4L1 / A1 ...[From (I) and (II)]
According to the given condition,
L2 = 2× L1 ....(I)
Let the cross sectional area of old wire be A1 and that of new wire be A2
According to the given condition,
2×A2 = A1 ....(II)
We know that,
R = L/A
R2 = L2 /A2
i.e. R2 = 4L1 / A1 ...[From (I) and (II)]
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