Question

if the roots alpha and beta of quadratic equation x square-5x +3(k-1)=0 are such that alpha - beta =11

Answer 1

Answer:

Step-by-step explanation:

X^2 - 5X + 3(k-1) = 0

α and β are roots.

α - β = 11  

√(b2 - 4ac) / 2a = 11

Squaring both sides

(b2-4ac)/4a^2 = 121

Here a = 1, b = -5, c = 3(k-1)

(25 - 12(k-1))/4 = 121

25 - 12(k-1) = 484

-12(k-1) = 459

k-1 = -459/12

k = 1 - 459/12

k = -447/12