Question

If the roots of kxsquar_7x+16==0 are reciprocal of each other then value of k is

Answer 1

Answer:

k = 16

Step-by-step explanation:

==: kx² - 7x + 16 = 0

Let zeroes be α and 1/α

Product of zeroes = c/a

α * 1/α = 16/k

1 = 16/k

k = 16

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Answer 2

Step-by-step explanation:

Let the roots be p and 1/p.

kx²-7x+16=0

Product of roots=constant/coeff of x²

p(1/p)=16/k

1=16/k

k=16

Therefore the value of k is 16