If the roots of the equation x² - bx + c = 0 be two consecutive integers, then b² - 4c equals
(a) -2
(b) 3
(c) 2
(d) 1
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Answer:
Answer is 1. Option d
Step-by-step explanation:
Let one root is a
∴ Other root will be a+1
(x-a)(x-(a+1))=x²-(2a+1)x+a(a+1)
Compare this with x²-bx+c
∴b=(2a+1) and c=a(a+1)
∴b²-4c=(2a+1)²-4a(a+1)
=4a²+4a+1-4a²-4a
=1
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