Question

Let f : (–1, 1) $\rightarrow$ R be a differentiable function with f(0) = -1 and f'(0) = 1. Let g(x) = [f(2f(x) + 2)]². Then g'(0) =
(a) –4
(b) 0
(c) –2
(d) 4

Answer 1

Answer:

Step-by-step explanation:

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