If the roots of the quadratic equation 2kx2-3kx + k + 1 = 0 are equal.
find the
values of k.
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Answer:
Step-by-step explanation:
Let p( x ) = 2kx² - 3kx + ( k + 1 ) = 0
Comparing p ( x ) with ax² + bx + c = 0,
We have a = 2k , b = - 3k and c = ( k + 1 ).
Discriminant =D = b² - 4ac= 0 = ( - 3k )² - 4 ( 2k ) ( k + 1 )=0
9k² - ( 8k² + 8k )= 0
9k² - 8k²+ 8k = 0
k² + 8k = 0
k ( k + 8 ) = 0
k + 8 = 0
k = - 8 is the answer.
Step-by-step explanation:
Let p( x ) = 2kx² - 3kx + ( k + 1 ) = 0
Comparing p ( x ) with ax² + bx + c = 0,
We have a = 2k , b = - 3k and c = ( k + 1 ).
Discriminant =D = b² - 4ac= 0 = ( - 3k )² - 4 ( 2k ) ( k + 1 )=0
9k² - ( 8k² + 8k )= 0
9k² - 8k²+ 8k = 0
k² + 8k = 0
k ( k + 8 ) = 0
k + 8 = 0
k = - 8 is the answer.
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