if the side of a square is tripled, how many times will it's area be as compared to the area of the original square
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If The Side of the Square is Normal means
Let we assume the side of square=a cm
Then area = a^2
Also if the Side is Triplet then means side=3a
Then area =9a^2.
So we see that 9 times area increases............
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let the side of the original square be x.
then , it's area = x^2
after increment,
side of square= 3x
ar. of square = (3x)^2 = 9x^2
ar.of original square/ar. of increased square = x^2/9x^2 = 1/9 =1:9
Therefore, the area increase 9 times
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