Question

If the side of the cube is increased by 10%,what is the percentage of increase in surface area

Answer 1

Answer:

21%

Step-by-step explanation:

for example :

let the side be : 50 cm

therefore it's surface area =

$6 \times l^{2}$

ie 6 x 50 x 50

= 15000 sq. cm

when it is increased by 10% the side becomes 55cm

therefore it's surface area =

$6 \times l {}^{2}$

ie 6 x 55 x 55

= 18150

therefore the difference is of 3150

$100 \times \frac{3150}{15000 } = 21percent$

Answer 2

Answer:

idk thank me later ok f***