If the sides of a triangle are b - 3a + 2c,
a + 3b - 3c and 2a - b + c, then find its
perimeter.
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Answer:
perimeter of triangle = 3b
Step-by-step explanation:
sides of triangle = (b - 3a + 2c) , (a + 3b - 3c) , (2a - b + c)
perimeter of triangle = sum of all sides
= (b-3a+2c) + (a+3b-3c) + (2a-b+c)
= b - 3a + 2c + a + 3b - 3c + 2a - b + c
= 3b + 3a - 3a + 3c - 3c
= 3b
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