Question

If the sides of the first rectangle are in the ratio 4: 3 and those of the second rectangle are in the ratio 2: 1,which rectangle is longer?

slove and explain.......

Answer 1

Let the ratio of first rectangle is 4x : 3x
Length is 4x
Breadth is 3x
Perimeter is 84 cm
2(l+b) = 84
2(4x+3x) = 84
7x = 42
x = 6
Length is 4x = 24 cm
Breadth is 3x = 18 cm

Ratio of second rectangle is 2x : 1x
Length is 2x
Breadth is 1x
Perimeter is 84 cm
2(l+b) = 84
3x = 42
x = 14 cm
Length is 2x = 28 cm
Breadth is 1x = 14 cm

Second rectangle is 4cm longer than first rectangle

Answer 2

Answer:

The first rectangle if longer.

Step-by-step explanation:

FIRST TRIANGLE:-

Let the length be '4x' and breadth be '3x'.

∴ The perimeter of the rectangle = 2(l+b)

                                                       = 2(4x + 3x)

                                                       = 2(7x)

⇒ The perimeter of the first rectangle if 14x.

SECOND RECTANGLE:-

Let the length be '2x' and the breadth be 'x'.

∴The perimeter of the rectangle = 2(l+b)

                                                      = 2(2x + x)

                                                      = 2(3x)

⇒ The perimeter of the second recatngle is 6x.

14x > 6x

∴From this, we can conclude that the first rectangle is longer.