Physics, asked by janhavigh, 9 months ago

If the speed of light, acceleration due to gravity, pressure are taken as fundamental quantities, the the dimensions of gravitational constant is​

Answers

Answered by arenarohith
6

Answer:

Explanation:Let us assume,

G=cxgyPzDimensional formula of G=[M−1L3T−2]

Dimensional formula of c=[M0L1T−1]

Dimensional formula of g=[M0L1T−2]

Dimensional formula of P=[M1L−1T−2]

[M−1L3T−2]=[M0L1T−1]x[M0L1T−2]y[M1L−1T−2]z[M−1L3T−2]=[M0+0+zLx+y−zT−x−2y−2z]

Comparing the coefficients,z=−1 ......... (1)

x+y−z=3 ......... (2)

−x−2y−2z=−2 . ........... (3)

Substitute equation (1) in (2) & (3)

x+y=2 ........(4)

−x−2y=−4 or, x+2y=4 ........ (5)

from (4) & (5),

we get,y=2x=0Hence,

G=c0g2P−1

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