if the sum of digit number and number obtained by reversing the digit is 44, find the find the sum of the digit of the 2 digit number
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2
let the two digit's number be 10A+B,
then
it's sum of digit's=A+B,
and number obtained after reversing it's digit's=10B+A,
then according to the question , we have
A+B+10B+A=44,
11A+11B=44,
11(A+B)=44,
then
A+B=4
then
it's sum of digit's=A+B,
and number obtained after reversing it's digit's=10B+A,
then according to the question , we have
A+B+10B+A=44,
11A+11B=44,
11(A+B)=44,
then
A+B=4
Answered by
1
no. =10y+x
no. obtain by reversing =10x+y
sum=10y+x+10x+y=44
11y+11x=44
y+x=4
no. obtain by reversing =10x+y
sum=10y+x+10x+y=44
11y+11x=44
y+x=4
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