Question

if the sum of first 11 terms is 33 then find 6th term
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Answer 1

Answer:

Hello mate..

Step-by-step explanation:

Step-by-step explanation:

Given  

An AP starts with a positive fraction and every alternate term is an integer. If the sum of the first 11 terms is 33, then the fourth term is

We know that in an A.P, a is the first term and d is the common difference.

Sum to n terms of an A.P will be n/2 (2a + (n – 1)d)

Given S11 = 33

So n/2 (2a + (n – 1)d) = 33

11/2 (2a + (11 – 1)d) = 33

11/2 (2a + 10d) = 33

11 (2a + 10d) = 66

Or a + 5d = 3

As every alternate term is an integer and sum is positive

So a + 3d = 2

Solving we get 2d = 1, or d = 1/2  

So a = 2 – 3(1/2)

Or a = 1/2  

Therefore a4 = a + 3d

                       = 1/2 + 3(1/2 )

                          = 2

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