If the sum of first m terms of an AP is 2m^2 + 3m, then what it it's second term ?
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Sum of first m terms = 2m^2 + 3m
Sum of 1st term
= 1st term
= 2(1)^2 + 3(1)
= 2 + 3 = 5
a = 5
Sum of 2 terms
= 2(2)^2 + 3(2)
= 2(4) + 6 = 14
Second term
= 14 - a
= 14 - 5
= 9
9 is your answer
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Sum of 1st term
= 1st term
= 2(1)^2 + 3(1)
= 2 + 3 = 5
a = 5
Sum of 2 terms
= 2(2)^2 + 3(2)
= 2(4) + 6 = 14
Second term
= 14 - a
= 14 - 5
= 9
9 is your answer
Mark as brainliest
Answered by
2
Answer:
second term is =9
Step-by-step explanation:
sum of 1 term =2*1^2+3*1=5
& 5 will be 1st term of this AP
now sum of 2 term = 2*2^2+3*2=14
2nd term = sum of 2 term - sum of 1 term
= 14-5
= 9
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