If the sum of first n even natural number is
240. find the value of n.
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Answer:
a=2 , d=2, sn= 420
sn= n/2[4+2n-2]
840=n[2+2n]
2n ka squar + 2n = 840
2( n ka squar + n)
n ka squar + n = 420
n ka squar+ ho 420=0
.......................
n = -b + √b ka squar - 4ac/2a
n=-1 +√1 -4×1×-420=2
-1+√1681/2
1+41-2
-1+41/2
=40/2
=20
sry yaar mujhe laga ki question ke last mai 420 hai isliye 420 prr hi bna diye hai sry if u can understand then okk and if u r not able to understand then tell me i will answer on 240 again
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