If the sum of first n terms of an ap is sn=5n^2+3n then find the 10th term of the
a.p.
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sum of first n terms of an ap
Sn = 5n^2 + 3n
So first term a = S1 = 5(1)^2 + 3(1)
= 5 + 3 = 8
a = 8
Second term a+d = S2 = 5(2)^2 + 3(2)
8+d = 20+6
8 + d = 26
d = 18
Tenth term = a + 9 d = 8 + 2(18) = 8 + 36 = 44
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Sn = 5n^2 + 3n
So first term a = S1 = 5(1)^2 + 3(1)
= 5 + 3 = 8
a = 8
Second term a+d = S2 = 5(2)^2 + 3(2)
8+d = 20+6
8 + d = 26
d = 18
Tenth term = a + 9 d = 8 + 2(18) = 8 + 36 = 44
mark as brainliest if it helps you!!
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