If the sum of roots of the quadratic equation x^2 - (p + 4) x + 5 is 0, then the value of p.
Answers
Answered by
0
Answer:
dtghn fhji hjkoo uilmg I'm gj
Answered by
0
Answer:
Given equation is
x 2
p(4x+
p−
1)+
2=
0
.
Comparing it with the
ax
2
+
bx+
c
, we get
D=
a= 1,b= 4p,c= (p
2
− p+ 2)
b 2
4ac
x 2
p(4x+
p−
1)+
2=
0
⇒
x 2
4xp+
p 2
p+
2=
0
⇒
(4p)
2
−
4(p
2
−
p+
2)=
0
⇒
16p
2
−
4p
2
+
4p−
8=
0
⇒
12p
2
+
4p−
8=
0
⇒
3p
2
+
p−
2=
0
⇒
3p
2
+
3−
2p−
2=
0
⇒
3p(p+
1)−
2(p+
1)=
0
⇒
(p+
1)(3p−
2)=
0
⇒
p=
−1
p=
3
2
Similar questions