Question

if the sum of squares of the zeroes of the quadratic polynomial x2-8x+k be 40, find k.

Answer 1

Hey !


★ Here is your answer ★



P(x ) = x² - 8x + k


a = 1 , b = -8 and c = k




Sum of zeroes = -b/a


Alpha + Beta = -(-8)/1


Alpha + Beta = 8


And


Product of zeroes = c/a

Alpha × Beta = k




A/q




( Alpha )² + ( Beta )² = 40


( Alpha + Beta )² - 2Alpha Beta = 40


( 8)² - 2 K = 40




64 - 2K = 40



-2k = 40 - 60



k = 10.