Question

If the sum of the age of father and son is 40 years and father is 3 times the son's age . Find their present age.​

Answer 1

$\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}$

Let the present age of father and son be 'x' and 'y' years respectively.

A/Q, we get two equations.

x + y = 40 ---> (1) and x = 3y ----> (2)

Now, solving equation (1)

=> x + y = 40

=> 3y + y = 40 (from equation 2)

=> 4y = 40

=> y = 10

Now, putting the value of 'y' in equation (2) we get,

=> x = 3y

=> x = 3(10)

=> x = 30.

Therefore,

The present age of father is 30 years and that of son is 10 years.

Answer 2

$\huge\bf{\underline{Answer:-}}$

$\rm{\underline{Given:}}$

Sum of ages of father and son is 40 years and the age of father is 3 times the son's age.

$\rm{\underline{To\:Find:}}$

Present ages of father and son.

$\rm{\underline{Solution:}}$

Let the present age of father be 'p' years and that of son be 'q' years.

According to the question -

$\sf{\implies\:p \: + \: q = 40........(i) }$

[Since, the sum of their ages is 40 years.]

Also,

$\sf{\implies\:p \: = 3q........(ii) }$

[ Father's age is three times the son's age]

Using equation (ii), equation (i) can be written as-

$\sf{\implies\:3q \: + \: q = 40}$

$\sf{\implies\:4q=40}$

$\sf{\implies\:q\:=\:\frac{40}{4} }$

$\sf{\implies\:q\:=10}$

Since, son's age =q = 10 years.

Therefore, father's age-

= p

=3q ......using (ii)

$\sf{=(3 \times 10)years}$

=30 years

Hence, the present ages of father and son are 30 years and 10 years respectively.