If the sum of the electrovalencies of Al in AICI3 and Mg in MgCl₂ is "Z" then the value of Z/4 is
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● Electrovalency of Al is +3 in AlCl3
{Let's tale electovalency of Al as X; X + (-3) = 0, as AlCl3 is a compound and should have net charge zero 》X= +3}
● Electovalency of Mg in MgCl2 is +2
{Let's take electovalency of Mg be Y; Y + (-2) = 0 》Y = +2}
So Z = 3 + 2 = +5
Hence Z/4 = +5/4
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