if the sum of the first n even natural number is 420 find the value of n
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1
is that ten???
please answer
please answer
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3
2 + 4 + 6 + 8 + ..... n = 420
Here,
Using Formula we have,
S(n) = n/2[2a + (n - 1)d]
Situation,
⇒ n/2[2 × 2 + (n - 1) × 2] = 420
⇒ n(2 + n - 1) = 420
⇒ n(n + 1) = 420
⇒ n² + n = 420
⇒ n² + n - 420 = 0
Factorize it,
⇒ n² + n - 420 = 0
⇒ n² + 21n - 20n - 420 = 0
⇒ n(n + 21) - 20(n + 21) = 0
⇒ (n + 21)(n - 20) = 0
⇒ n + 21 = 0
⇒ n = -21 [Not Applicable]
Or
⇒ n - 20 = 0
⇒ n = 20
Therefore,
Value on n = 20
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