if the sum of the zeroes of ky+2y+3k is equal to twice their product,find the value of k
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Hi!
Here's your answer>>>>
Let the zeroes be alpha and beta.
Product of zeroes=c/a
alpha×beta=k/k
alpha × beta=1 (1)
Sum of zeroes=-b/a
Alpha+beta=-2/k (2)
A.T.Q.
Sum of zeroes=2{product of zeroes}
alpha+beta=2{alpha×beta}
From Equation 1 and 2
-2/k=1
-2=k
HENCE value of k is -2
HOPE that this will help you ☺☺☺☺☺
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Here's your answer>>>>
Let the zeroes be alpha and beta.
Product of zeroes=c/a
alpha×beta=k/k
alpha × beta=1 (1)
Sum of zeroes=-b/a
Alpha+beta=-2/k (2)
A.T.Q.
Sum of zeroes=2{product of zeroes}
alpha+beta=2{alpha×beta}
From Equation 1 and 2
-2/k=1
-2=k
HENCE value of k is -2
HOPE that this will help you ☺☺☺☺☺
Please mark it as brainliest ☺☺☺☺☺☺
naman176:
hey
in the statement it is ky square.i dont know how to type ky square
so plzz give ur ans. acc. to it
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