if the sum of three consecutive natural numbers is 63 then find the smallest number
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Answered by
1
Answer:
Let the smallest Number be X
Consecutive numbers = x, (x+1) and (x+2)
= X+x+1+x+2 = 63
= 3x = 63-3
= 3x = 60
= x = 20
Answered by
0
Answer:
21
Step-by-step explanation:
Let,a-d,a,a+d are the consecutive natural numbers.
According to given condition,
a-d+a+a+d =63
3a=63
a =21
now,
d =
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