if the sum of three consecutive numbers is 213 ,find the numbers
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Answered by
17
Let the first number be x
Therefore the second number is x+1
and the third number is x+2
x+x+1+x+2= 213
3x+3= 213
3x= 213-3
3x= 210
x= 210/3
x= 70.
Answer: The first number is 70.
The second number is 70+1= 71
The third number is 70+2= 72.
Hope it helps! :)
Therefore the second number is x+1
and the third number is x+2
x+x+1+x+2= 213
3x+3= 213
3x= 213-3
3x= 210
x= 210/3
x= 70.
Answer: The first number is 70.
The second number is 70+1= 71
The third number is 70+2= 72.
Hope it helps! :)
Answered by
10
Heya !!!
Let the numbers be x , x+1 and x+2
sum of the three consecutive numbers = 213
then
x + x + 1 + x + 2 = 213
3x + 3 = 213
3x = 213 -3
3x = 210
x = 210/3
x = 70
then the numbers , x = 70 ,x +1 = 70 + 1 = 71 and x + 2 = 72
hope this helps you :)
please mark as brainliest
Let the numbers be x , x+1 and x+2
sum of the three consecutive numbers = 213
then
x + x + 1 + x + 2 = 213
3x + 3 = 213
3x = 213 -3
3x = 210
x = 210/3
x = 70
then the numbers , x = 70 ,x +1 = 70 + 1 = 71 and x + 2 = 72
hope this helps you :)
please mark as brainliest
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