If the sum of three natural consecutive number is 144.find the number
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sum of three consecutive numbers are x +1, x +2 , x+3 ,
sum of three numbers x +1 + x+2 +x+3 = 144
3x + 6 = 144
3x = 138
x = 46,
the number is 46,
46 +1,46+2,46+3
47,48,49
sum of three numbers x +1 + x+2 +x+3 = 144
3x + 6 = 144
3x = 138
x = 46,
the number is 46,
46 +1,46+2,46+3
47,48,49
Shivampaliwal14:
Thanks
Answered by
1
let the no. be x+1,x+2and x+3..
then 3x+6=144..
3x=144-6..
3x=138
x=138/3
x= 46..
then the nos, are 46+1 46+2 and 46+3 ie
47,48and 49
then 3x+6=144..
3x=144-6..
3x=138
x=138/3
x= 46..
then the nos, are 46+1 46+2 and 46+3 ie
47,48and 49
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