Question

In TriangleABC , Right angled at B. AB = 5cm and BC+AC =25CM. find the value of SinA, CosA , SecC.

Answer 1

(Ac)2=(25-bc) 2 Using pythagorus th Ac2=ab2+bc2 Using value of ac n ab Bc =12cm Therefore ac =13 cm Sin a =12/13 Cos a=5/ 13 Sec c=13/ 12

Answer 2

AC=13 and BC=12 therefore SinA=12/13  CosA=5/13 and SecA=13/5