Question

if the sum of zeros of the quadratic polynomial 3 x square - kx + 6 is 3 then find the value of k

Answer 1

Given: The sum of zeros of quadratic polynomial $3 {x}^{2} - kx + 6$ is 3.

To find: The value of k

Solution: In a quadratic polynomial p(x) given by the expression $a {x}^{2} + bx + c$:

The sum of zeros = -b/a

Product of zeros= c/a

In the given polynomial, a = 3, b= -k and c=6

Here,

Sum of zeros

= -b/a

= -(-k)/3

= k/3

But, the sum of zeros is equal to 3 as given in the question.

Therefore,

k/3 = 3

=> k = 3×3

=> k = 9

Therefore, the value of k is equal to 9.

Answer 2

Answer:

k = 9

Find the steps in the attachment.

Hope it helps...