Question

If the terminal speed of a sphere of gold
(density = 19.5 kg/m3) is 0.2 m/s in a
viscous liquid then find the terminal
speed of sphere of silver (density = 10.5
kg/m3) of the same size in the same
liquid (density = 1.5 kg/m3).
a a ni (ad = 1.5 kg/m3)​

Answer 1

Answer:

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Answer 2

Answer:

Terminal speed of sphere of silver(Ag) = 0.1 m/s

Explanation:

Given,

Terminal speed of a sphere of gold (density = 19.5 kg/m^3) is 0.2 m/s.

the terminal speed of sphere of silver (density = 10.5 kg/m^3) of the same size in the same liquid (density = 1.5 kg/m^3).

We know,

Terminal speed is given as:

$v_T = \dfrac{2r^2(\rho - \sigma)g}{9\eta}$

where, ρ = density of substance of body

and, σ = density of liquid

Then,

$\dfrac{v_T(Ag)}{v_T(Au)} = \dfrac{\rho_{Ag}-\sigma_1}{\rho_{Au}-\sigma_2}\\\\v_T(Ag) = \dfrac{10.5-1.5}{19.5-1.5}\times0.2\\\\v_T(Ag) = 0.1\ m/s$