Question

If the two circles x² + y2 +2gx 2fy+c = 0 then dy/dx​

Answer 1

Answer:

The answer is $\frac{dy}{dx} = -\frac{x+g}{y+f}$

Step-by-step explanation:

I think the only given equation is $x^{2}+y^{2}+2gx+2fy+c=0$.

On differentiating both side we get,

$2x+2y\frac{dy}{dx}+2g+2f\frac{dy}{dx} = 0$

$x+y\frac{dy}{dx}+g+f\frac{dy}{dx} = 0$

$(y+f)\frac{dy}{dx} = -(x+g)$

$\frac{dy}{dx} = -\frac{x+g}{y+f}$