Question

If the two dice are rolled then find the probability of getting the product of face value of 6 or the difference of face values of 5.​

Answer 1

Answer:

p(product as six )= 4/36

Answer 2

The probability of getting the product of face value of 6 or the difference of face values of 5. is $\dfrac{1}{9}$ .

Step-by-step explanation:

If two dice rolled , then the total number of outcomes are 36.

Favorable outcomes for getting the product of face value of 6 : (2,3) , (3,2) , (1,6) , (6,1)

Favorable outcomes for getting difference of face values of 5.: (6,1), (1,6)

Since ,  (6,1), (1,6) are common in both , then

Favorable outcomes for getting the product of face value of face value of 6 or the difference of face values of 5.​ = : (2,3) , (3,2) , 1,6) , (6,1)

Now , the required probability will be :

$\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}\\\\=\dfrac{4}{36}=\dfrac{1}{9}$

Hence, the required probability is $\dfrac{1}{9}$ .

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