Question

if the two directional cosines of a vectors are 1√2and 1√3 then the value of third directional cosines is​

Answer 1

Explanation:

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Answer 2

Answer: 1/√6

Explanation:

x^2 + y^2 + z^2 = 1

here let x = 1/√,20 '

and y = 1/√3

then, (1/√2)^2 + (1/√3)^2 + z^2 = 1

1/2 + 1/3 + z^2 = 1

5/6 + z^2 = 1

z^2 = 1 - 5/6

z^2 = 1/6

z = 1/√6

Hope you understand....

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