Question

If the vector f =4i-10j and vector r=5i-3j, then calculate the torque.(T=rxf)

Answer 1

see the attachment for the answer

Answer 2

The torque acting on the body is (38k) N-m.

Explanation:

It is given that,

Force, $F=(4i-10j)\ N$

Position vector, $r=(5i-3j)\ N$

We need to find the torque. It is given by the cross product of position and force such that,

$\tau=r\times F$

$\tau=(5i-3j)\times (4i-10j)$

Using cross product of two vectors, we get :

$\tau=\begin{pmatrix}0&0&38\end{pmatrix}$

$\tau=(38k)\ N-m$

So, the torque acting on the body is (38k) N-m. Hence, this is the required solution.

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