Question

If the vertices of a triangle are (5,6), (1,2)
and (9, 2). Show that the triangle is right
angled.​

Answer 1

Step-by-step explanation:

In right angled triangle sum of the square of two sides is equal to squate of third side

A (1,2) , B (5,6) , C (9,2)

AB^2=(5-1)^2+(6-2)^2

=32

BC^2=(9-5)^2+(2-6)^2

=32

AC^2=(9-1)^2+(2-2)^2

=64

64=32+32

64=64

Hence these are the vertices of a right angled triangle.