if the volume of a given mass of a gas at STP is 52 cubic metre what will be its volume at the pressure of 104 CM HG and temperature remaining constant
Answers
Given info : if the volume of a given mass of a gas at STP is 52 cubic metre and Temperature remains constant.
To find : the volume of gas at the pressure of 104 cm Hg is ...
solution : initial volume, V₁ = 52 m³
initial pressure, P₁ = 76 cm Hg [ for STP ]
final volume, V₂ = ?
final pressure , P₂ = 104 cm Hg
for isothermal process (temperature remains constant),
P₁V₁ = P₂V₂
⇒52 m³ × 76 cm Hg = V₂ × 104 cm Hg
⇒V₂ = 38 m³
Therefore the volume of gas at the pressure of 104 cm Hg is 38 m³.
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Given :-
☆volume of given mass of a gas at STP is 52 cubic metre what will be its volume at the pressure of 104 CM of HG temperature remaining constant
Solution :-
P₁V₁ = P₂V₂
(100)(52) = (138.32)(V₂)
5200 = 138.32V₂
5200/138.32 = V₂
37.5 = V₂