Question

If the volume of the cube is 729 cu m , then the total surface area of the cube is

Answer 1

$729 = {a}^{3 } \\ 9 = {a}$

$vol \: of \: cube = {a}^{3}$
TSA of cube =6a^2
TSA=6×9^2
=6×81
=486 sq m

Answer 2

let the side of square be =a
volume =a^3=729
a=
$\sqrt[3]{729}$
=9m
a=9m
total surface area =6a^2=6*9*9= 486