Question

if the work done by a water heater is 200 joules,what is the time in which the heater would have used 2 amperes and 2 volts.

Answer 1

Answer:

Explanation:

POWER = WORK DONE / TIME TAKEN

POWER = VOLTAGE × CURRENT  

∴ V × I = W/t

2 × 2= 200/ t

t = 200/4

time taken = 50 sec

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Answer 2

The time for which the water heater is running is equal to 50 second

Explanation:

• The Power is equal to the the product of the current flowing in the circuit and the potential difference.
• Your the current is equal to 2 ampere and the potential difference is 2 volt , hence the power is 2x2 = 4 Watt
• Now the power is the work done per unit second

Or power = $\frac{work done}{time}$

Or time = $\frac{work done}{power}$

= 200joule/ 4 Watt = 50 second

Change the time taken for generation of 200 dual of heat if the efficiency is 100% is equal to 50 seconds

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