Question

If the zeroes of the polynomial x^3-3x^2+x+1are a-b,a,a+b,find a and b.

Answer 1

Here is your answer
Select my answer as brainliest if it will help you

Answer 2

By comparing the above p(x) with this

p(x)= a³+b²+c+d
Here is this p(x) , a= 1, b= -3, c= 1, d=1

sum of the zeroes = (-b/a)

sum of the zeroes = (a-b)+(a+b)+a=3a i.e. 3a = -b/a

or 3a=3

or a=1

product of the zeroes= (-d/a)

product of the zeroes = (a-b)*(a+b)*a=
a3 - ab² i.e. 1 - b²= (-d/a)
(by putting the value a=1)

1 - b²= (-1/1)

1 - b² = -1
b² =2
b = +✓2 or -✓2



hope this helps you