Question

if the zeroes of the polynomial x2-px=q are 3 and 2 , find the values of p and q.

Answer 1

p ( 2 )

= (2)^2 - 2p = q

= 4 - 2p = q ... ( 1)

P(3)

= (3)^2 - 3p = q

= 9 - 3p = q. ...... (2)

From 1 and 2 ..

4 - 2p = 9 - 3p

4 - 9 = -3p + 2p

-5 = -p

p = 5 Ans.

Q = 4 - 2p = 4 - 2*5 = -6

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that the zeroes of the polynomial $x^2-px=q$ are $3$ and $2$

To Find:-

We have to find that the values of $p$ and $q$

Solution:-

According to the problem

When $x=3$

$3^2-p(3)=q\\9-3p=q....(i)$

When $x=2$

$2^2-p(2)=q\\4-2p=q...(ii)$

Putting the value of $q$ from equation $(i)$ in equation $(ii)$, we get

$4-2p=9-3p\\-2p+3p=9-4\\p=5$

By putting the value of $p$ in equation $(ii)$, we get

$4-2p=q\\4-2(5)=q\\4-10=q\\-6=q$

Final Answer:-

The correct answer are $5$ and $-6$ respectively.

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