Question

If the zeroes of the quadratic polynomial x2 + (a + 1)x + b are 2 and -3, find the value of a and b. ​

Answer 1

x²-px-p-c = 0

a+b = p

ab = -p-c

now, (a+1)(b+1)

= ab+a+b

=-p-c+p

= -c

please mark as brainliest if you understand ☺️

Answer 2

Step-by-step explanation:

x

2

+(a+1)x+b is the quadratic polynomial.

2 and −3 are the zeros of the quadratic polynomial.

Thus, 2+(−3)=

1

−(a+1)

=>

1

(a+1)

=1

=>a+1=1

=>a=0

Also, 2×(−3)=b

=>b=−6

I am not sure with the answer