if the zeros of a polynomial p(x)=are √2, -√2 ,1/2 , and respectively then find the polynomial p(x).
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ashamonikakati2:
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Answered by
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Answer:
Step-by-step explanation:
as zeroes r given
let
x=√2, y=-√2 ,z=1/2
as 3 zeroes are present so its a cubic polynomial
x3-[x+y+z]x2+[x+y+z]x-[x*y*z]------1
now put the values here above given =en 1
sorry i cancelled 1 step
x3-1/2x2+1/2x-1
after cross multiplying final result is
4x3-2x2+2x-1=0
i dont know ,its right or wrong
if its wrong u can report it
thnxxx
it s ok
the required answer is 2x^3 - x^2 - 4x+2
give me the proof of formulla
i will give mine dude
if a, b, c are zeros then the polynomial is (x-a) (x-b) (x-c) =x^3 - (a+b+c) x^2 +(ab+bc+ca) x-abc
hyy i u r right but i m too right use mine formulla u will get answer
i did mistake in cross multiplication
otherwise there is another way
to find the polynomials
leave it brother. my intention is not to point out
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