Question

if theta = 60° , show that tan theta = root 1-cos square theta / cos theta

Answer 1

α=60
tanα=√3=RHS
Now, √1-cos^α =sinα =√3/2
cosα=1/2
(√1-cos. ^2α)/cosα=(√3/2)/(1/2)=√3=LHS
LHS=RHS...HENCE PROVED